Description:
Given a binary tree, return the inorder traversal of its nodes’ values. Example:
Input: [1,null,2,3]1
2
3
4
51
\
2
/
3
Output: [1,3,2]
Follow up: Recursive solution is trivial, could you do it iteratively?
解法:
直接递归的方法解题,具体代码如下:1
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15class Solution {
public List<Integer> inorderTraversal(TreeNode root) {
List<Integer> output = new ArrayList();
helper(root,output);
return output;
}
void helper(TreeNode root,List<Integer> output){
if(root == null){
return;
}
helper(root.left,output);
output.add(root.val);
helper(root.right,output);
}
}